JS每日一题：写一个mySetInterval，每次间隔a, a+b, a+nb，执行fn函数 执行n次之后 自动关闭定时器

写一个mySetInterval(fn, a, b, n)
每次间隔a, a+b, a+nb
执行fn函数 执行n次之后 自动关闭定时器

class MySetInterval {
    constructor(fn, a, b, n){
        this.fn = fn;
        this.a = a;
        this.b = b;
        this.n = n;
        this.count = 0;
        this.timer = null;
    }

    start(){
        const time = this.a + this.count * this.b
        this.timer = setTimeout(()=>{
            this.count++
            this.fn()
            console.log(time)
            this.start()
        }, time)
        if(this.count > this.n){
            clearTimeout(this.timer)
        }
    }
}

const mySetTimeInterval = new MySetInterval(()=>{
    console.log('123123123')
},1000, 2000, 3)

mySetTimeInterval.start()